This is the problem:
(a) exactly six of the balls drawn are green;
(b) at least two of the balls drawn are yellow;
(c) at most four of the balls drawn are red.
This is how I solve it:
For the first subsection I used this formula:
- "n" is the number of attempts
- "k" is the number of successes
- "p" is the probability of successes
Substitution and answer:
- "p" is the probability of successes
- "k" is the number of successes
- "n" is the number of attempts
- "u" is k success
And for the last subsection this is the formula:
- "P" is the probability of the event,
- "C" (n, k) are the combinations of k elements from n elements
- "p" is the probability of success and q = (1-p) the probability of failure
- "n" is the number of times that we repeat the individual case
- "k" is the number of successes
Checa el comentario que puse para Obed. 2 pts extra.
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